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Comments (4) vcmsowc (24.8.2013 2:45)
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Fidz (10.11.2012 16:52)
Draw a Perpendicular from "E" to "AB"Let it meet "AB" at "O"Consider the Triangles AEO and ABCThey are SIMILAR because angle "C" is 90 (Angle in a Semicircle!Angle "C"=Angle "O"=90Angle "A" is comomn)Therefor AE/AO = AB/ACThat is AE*AC=AB*AO______.(1)Similarly from the similar triangles BEO and BAD,BE/BO=AB/BDThat is BE*BD=AB*BO____.(2)(1)+(2)=_ AB(AO+BO)=(AC*AE)+(BD*BE)That is AB*AB=(AC*AE)+(BD*BE)HENCE THE ANSWER!!!ASWATHY VARMACLASS XICOCHIN REFINERY SCHOOLAMBALAMUGAL.
Fidz (10.11.2012 16:52)
Draw a Perpendicular from "E" to "AB"Let it meet "AB" at "O"Consider the Triangles AEO and ABCThey are SIMILAR because angle "C" is 90 (Angle in a Semicircle!Angle "C"=Angle "O"=90Angle "A" is comomn)Therefor AE/AO = AB/ACThat is AE*AC=AB*AO______.(1)Similarly from the similar triangles BEO and BAD,BE/BO=AB/BDThat is BE*BD=AB*BO____.(2)(1)+(2)=_ AB(AO+BO)=(AC*AE)+(BD*BE)That is AB*AB=(AC*AE)+(BD*BE)HENCE THE ANSWER!!!ASWATHY VARMACLASS XICOCHIN REFINERY SCHOOLAMBALAMUGAL.
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